Question

1. A container holds 0.320 m^3 of oxygen at an absolute pressure of 6.00 atm. A valve is opened, allowing the gas to drive a piston, increasing the volume of the gas until the pressure drops to 1.50 atm. If the temperature remains constant, what new volume does the gas occupy?

2. Oxygen O2 molecules move with an rms speed of 452 m/s in a gas. What is the temperature of the gas? Assume the gas is uniform temperature throughout.

Answer 1

(1)

Apply the ideal gas equation

PV = nRT

If temperature is constant then

PV = Constant

V2/V1 = P1/P2

V2 = V1*(P1/P2) ........ (1)

V1 = 0.32 m^3

P1 = 6 atm

P2 = 1.5 atm

Use equation (1).

V2 = 0.32*6/1.5

V2 = 1.28 m^3

(2)

Write the equation for the V_rms.

V_rms = Sqrt{3RT/M}

     452 = Sqrt{(3*8.3*T)/(2*16*10^-3)}

204304 = (24.9T)/(32*10^-3)

T= 262.56 K

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