Question

an electron is projected with a velocity of 3 x 10^7 m/s East into a uniform magnetic field of 4 T downward.

a) find the magnitude and direction of the force on the electron.

b) what will be the radius of the circular path of the electron?

Answer #1

An
electron (mass 9.11x kg) travels at 2x10^5 m/s to the left. A
magnetic field of magnitude 1.2 T points out of the page.
a) What is the force (magnitude and direction) on the
electron?
b) What is the acceleration of the electron?
c) If the magnetic field is uniform in this region, the
electron will follow a circular path. What is the radius of the
circle?
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work

An electron that has a velocity with x component 1.9 × 106 m/s
and y component 3.4 × 106 m/s moves through a uniform magnetic
field with x component 0.033 T and y component -0.15 T. (a) Find
the magnitude of the magnetic force on the electron. (b) Repeat
your calculation for a proton having the same velocity.

An electron that has a velocity with x component 2.0 × 106 m/s
and y component 3.9 × 106 m/s moves through a uniform magnetic
field with x component 0.035 T and y component -0.21 T. (a) Find
the magnitude of the magnetic force on the electron. (b) Repeat
your calculation for a proton having the same velocity.

An electron beam is fired horizontally from an electron gun with
a velocity of 3.00 x 10^7 m/s in the +x direction. A uniform
magnetic field of magnitude 0.250 T in the –z direction is then
applied.

An electron moves with a velocity, v = ( 4i + 2 j)x106 m/s in a
region where there is a uniform magnetic field, B = (0.5 j) T. (a)
Find the magnitude and direction of the force acting on the
electron as it enters into the magnetic field.(b) Find the pitch of
the helical motion. (c) What is the work done by the magnetic force
during 1 cycle of the motion? (e = - 1.6x10-19 C, me = 9.10...

A proton, traveling with a velocity of 6.8 x 106 m/s
due east, experiences a maximum magnetic force of 8.0 x
10-14 N. The direction of the force is straight down,
toward the surface of the earth. What is the magnitude and
direction of the magnetic field B, assumed perpendicular to the
motion?

1. An electron enters a magnetic field of magnitude 1.75T
directed vertically upward. If the electron’s initial velocity was
4.7x10^6 m/s, what is
a) the magnitude and direction of the magnetic force on the
electron.
b) the radius of its circular path.

An electron (q=-1,6x10-19C, m=9,1x10-31kg)
enters a uniform magnetic field, whih is in +x axis and it has
magnitude of 2T. At t=0, the velocity components
vx=3x105m/s,
vy=4x105m/s and vz=0.
a-At t=0 calculate the magnetic force acting on proton and its
acceleration.
b- Calculate the Radius of helical path
c- Calculate the angular velocity
d- Calculate the pitch of helix. (0=4x10-7
MKS)
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a) An electron has a velocity of 7.0 x 106 m/s in the
positive x direction at a point where the magnetic field has the
components Bx = 3.0 T, By = 2.5 T, and Bz =
2.0 T. What is the magnitude of the acceleration of the electron at
this point (in 1018 m/s2)? (me = 9.11 x
10-31 kg, e = 1.6 x 10-19 C)
b) A particle (q = 5.0 nC, m = 3.0 μg) moves in...

Determine the magnitude of the force on an electron traveling
6.55×105 m/s horizontally to the east in a vertically
upward magnetic field of strength 0.70 T .
Determine the direction of the force on an electron.

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