Question

I need to see all the steps please! I know there are calculations of this kind of question out there.

An inquisitive physics student and mountain climber climbs a 51.0-m-high cliff that overhangs a calm pool of water. He throws two stones vertically downward, 1.00 s apart, and observes that they cause a single splash. The first stone has an initial speed of 2.02 m/s.

(a) How long after release of the first stone do the two stones hit the water?
s

(b) What initial velocity must the second stone have if the two stones are to hit the water simultaneously?

magnitude	m/s
direction	---Select--- upward downward

(c) What is the speed of each stone at the instant the two stones hit the water?

first stone	m/s
second stone	m/s

Answer 1

mountain climber stands at the top of a 51.0 m cliff that overhangs a calm pool of water. He throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. The first stone has an initial velocity of 2.02 m/s.

The 2nd stone must travel the 51.0 m downward in 1 second less than the 1st stone. Since both stones fall downward, I choose downward as positive direction.

Initial velocity = +2.02 m/s
Acceleration = +9.8 m/s^2
Displacement = +51.0 m

Let