Question

A large punch bowl holds 3.95 kg of lemonade (which is essentially water) at 20.0

A large punch bowl holds 3.95 kg of lemonade (which is essentially water) at 20.0

Homework Answers

Answer #1

Apply First Law of Thermodynamics :
--------------------------------------...
Q = [ Delta U sub I ] + [ Delta U sub W ] + W sub B

Q ~ 0.0 & W sub B = 0.0

[ Delta U sub I ] = [ mI ] [ CPI ( 0.0 - (-10.2) ) + HSF + CPW ( TE - 0.0 ) ]

[ Delta U sub I ] = [0.370 ] [( 1.96 ) ( (10.2 ) + 335 + ( 4.187 ) ( TE ) ]

[ Delta U sub I ] = [ 7.397 + 123.95 + ( 1.549 ) ( TE ) ]

[ Delta U sub I ] = 131.347 + ( 1.549 ) ( TE )

[ Delta U sub W ] = [msubW] [ CPW ( TE -20.0 )]

[ Delta U sub W ] = [ 4.05 ] [ (4.187)( TE ) - 83.74 ]

[ Delta U sub W ] = (16.95735 )( TE ) - 339.147

0.0 = [ 131.347 + 1.549 ( TE ) ] + [ (16.95735 )( TE ) - 339.147 ]

(18.51) ( TE ) = 207.8

TE = 11.23 deg C <-------------------------------

m sub I remaining = 0.0 kg <---------------------------------

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A large punch bowl holds 3.25 kg of lemonade (which is essentially water) at 20.0° C....
A large punch bowl holds 3.25 kg of lemonade (which is essentially water) at 20.0° C. A 1.90-kg ice cube at −10.2°C is placed in the lemonade. What is the final temperature of the system, and the amount of ice (if any) remaining? Ignore any heat exchange with the bowl or the surroundings.
A large punch bowl holds 3.70 kg of lemonade (which is essentially water) at 25.0 ∘C....
A large punch bowl holds 3.70 kg of lemonade (which is essentially water) at 25.0 ∘C. A 6.00×10−2-kg ice cube at -11.0 ∘C is placed in the lemonade. What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings. What is the amount of ice (if any) remaining?
A large punch bowl holds 3.80 kg of lemonade (which is essentially water) at 22.0 ∘C....
A large punch bowl holds 3.80 kg of lemonade (which is essentially water) at 22.0 ∘C. A 6.00×10−2-kg ice cube at -15.0 ∘C is placed in the lemonade. What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings. Give your answer in degrees C.
A large punch bowl holds 3.70 kg of lemonade (which is essentially water) at 25.0 ∘C∘C....
A large punch bowl holds 3.70 kg of lemonade (which is essentially water) at 25.0 ∘C∘C. A 5.90×10−2-kg ice cube at -12.0 ∘C is placed in the lemonade. What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings.
A large punch bowl holds 3.30 kg of lemonade (which is essentially water) at 25.0 ∘C....
A large punch bowl holds 3.30 kg of lemonade (which is essentially water) at 25.0 ∘C. A 5.50×10^(−2) kg ice cube at -13.0 ∘C is placed in the lemonade. a.What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings. Answer in degree C b.What is the amount of ice (if any) remaining? Answer in kg
A large punch bowl holds 3.50 kgkg of lemonade (which is essentially water) at 22.0 ∘C∘C....
A large punch bowl holds 3.50 kgkg of lemonade (which is essentially water) at 22.0 ∘C∘C. A 5.10×10−2-kgkg ice cube at -10.0 ∘C∘C is placed in the lemonade. What is the final temperature of the system? Ignore any heat exchange with the bowl or the surroundings. What is the amount of ice (if any) remaining?
A 7kg glass bowl contains 16kg of punch at 25oC. Two and a half kilograms of...
A 7kg glass bowl contains 16kg of punch at 25oC. Two and a half kilograms of ice is added to the punch. The ice has an initial temperature of -20oC. Assume no transfer of heat to the external environment when equilibrium is reached, all the ice has melted and the final temperature of the mixture is above 0oC. Determine this temperature? Cglass = 840 J.kg-1.oC Cice = 2000 J.kg-1.oC Latent heat of fusion of water, Lw = 335,000 J/kg
A 190 g copper bowl contains 110 g of water, both at 20.0°C. A very hot...
A 190 g copper bowl contains 110 g of water, both at 20.0°C. A very hot 430 g copper cylinder is dropped into the water, causing the water to boil, with 2.42 g being converted to steam. The final temperature of the system is 100°C. Neglect energy transfers with the environment. (a) How much energy is transferred to the water as heat? (b) How much to the bowl? (c) What is the original temperature of the cylinder? The specific heat...
A 0.033 kg glass (with c = 840 J/kg oC) contains 0.281 of lemonade which, due...
A 0.033 kg glass (with c = 840 J/kg oC) contains 0.281 of lemonade which, due to the sugar content, has a specific heat of 4,208 J/kg oC. After putting 0.049 kg of ice into the glass and allowing it to completely melt the final equilibrium temperature of the glass of lemonade is found to be 2.9 oC. intial temperature is 0. (a) Calculate the initial temperature of the lemonade and glass. oC Note the following data for ice/water: specific...
A 170 g copper bowl contains 245 g of water, both at 20.0°C. A very hot...
A 170 g copper bowl contains 245 g of water, both at 20.0°C. A very hot 300 g copper cylinder is dropped into the water, causing the water to boil, with 5.45 g being converted to steam. The final temperature of the system is 100°C. Neglect energy transfers with the environment. (c) What is the original temperature of the cylinder? (in celcius)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT