In 35.0 s, a pump delivers 0.550 m3 of oil into barrels on a platform 25.0 m above the pump intake pipe. The density of the oil is 0.820 g/cm3.
a. Calculate the work done by the pump.
b. Calculate the power produced by the pump.
a. Calculate the work done by the pump.
Mass lifted = (0.550 m3) x (1.00 x 106 cm3/m3)(0.820 g/cm3)
= 4.51 x 105 g = 451 kg
The work done is
W = Fgd = mg (h) = (451 kg)(9.80 m/s2)(25.0 m)
= 1.10 x 105 J = 1.10 x 102 kJ
b. Calculate the power produced by the pump.
P = W / t = 1.10 x 102 kJ / 35s = 3.14 kW
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