Question

A straight, vertical wire carries a current of 2.30 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has a magnitude of B = 0.550 T and is horizontal.

A) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is east? Express your answer with the appropriate units.

B) What is the direction of this magnetic force? (North/South/East/West)

C) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is south? Express your answer with the appropriate units.

D) What is the direction of this magnetic force? (North/South/East/West)

E) What is the magnitude of the magnetic force on a 1.00 cm section of the wire that is in this uniform magnetic field, if the magnetic field direction is 30.0 ∘ south of west? Express your answer with the appropriate units.

F) What is the direction of this magnetic force? Express your answer in degrees north of west.

Answer 1

a)

F = ILBsin

F = 2.30 * 0.01 * 0.55 * sin 90

F = 0.01265 N

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b)

south (using right hand rule)

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c)

F = ILBsin

F = 2.30 * 0.01 * 0.55 * sin 90

F = 0.01265 N

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d)

west

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e)

now angle is 30 degree

so,

F = 2.30 * 0.01 * 0.55 * sin 90

F = 0.01265 N

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f)

= 60 degree ( North of west)