Question

A proton (mass = 1.67x10^27 kg, charge = 1.60x10^19 C) moves
from point A to point B under

the influence of an electrostatic force only. At point A the proton
moves with a speed of 50

km/s. At point B the speed of the proton is 80 km/s. Determine the
potential difference VB-VA.

I know the answer is -20, but I'm not sure how to get it...thanks!

Answer #1

Mass(m) of proton = 1.67*10^{-27}kg

Charge(q) of proton = 1.6*10^{-19}C

Speed(v_{A}) of proton at the point A = 50m/s

Speed(v_{B}) of proton at the point B = 80m/s

Now the formula for the potentialdifference
V_{B}-V_{A} is calculated by using theformula

.........................(1)

Substitute all the given values in the equation (1) we get
therequired value.

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