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A proton (mass = 1.67x10^27 kg, charge = 1.60x10^19 C) moves from point A to point...

A proton (mass = 1.67x10^27 kg, charge = 1.60x10^19 C) moves from point A to point B under
the influence of an electrostatic force only. At point A the proton moves with a speed of 50
km/s. At point B the speed of the proton is 80 km/s. Determine the potential difference VB-VA.

I know the answer is -20, but I'm not sure how to get it...thanks!

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Answer #1

Given that
Mass(m) of proton = 1.67*10-27kg
Charge(q) of proton = 1.6*10-19C
Speed(vA) of proton at the point A = 50m/s
Speed(vB) of proton at the point B = 80m/s
Now the formula for the potentialdifference VB-VA is calculated by using theformula
        
       .........................(1)
Substitute all the given values in the equation (1) we get therequired value.

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