Question

A 4.71 kg mass moving in space according to v= (6.00t2 - t)i + (15.0t2)j +(t3...

A 4.71 kg mass moving in space according to v= (6.00t2 - t)i + (15.0t2)j +(t3 + 3.14t)k (relative to the origin), with v in meter/second and t in seconds. At t= 1.57s (a) what are the magnitude and direction of the force acting on the mass (b) what is the angle between the acceleration and velocity vector (c) what is the average velocity? (d) What is the mass angular momentum relative to the origin? (e) What is the torque acting on the mass relative to the origin? (f) What is the work done by this force from t=0 s to t=1.57 s? (g) What is the instantaneous power at t= 1.57 s?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The position ? of a particle moving in space from (t=0 to 3.00 s) is given...
The position ? of a particle moving in space from (t=0 to 3.00 s) is given by ? = (6.00?^2− 2.00t^3 )i+ (3.00? − ?^2 )j+ (7.00?)? in meters and t in seconds. Calculate (for t = 1.57 s): a. The magnitude and direction of the velocity (relative to +x). b. The magnitude and direction of the acceleration (relative to +y). c. The angle between the velocity and the acceleration vector. d. The average velocity from (t=0 to 3.00 s)....
At time t = 0, a 4.0 kg particle with velocity v with arrow = (5.0...
At time t = 0, a 4.0 kg particle with velocity v with arrow = (5.0 m/s) i hat − (6.0 m/s) j is at x = 4.0 m, y = 2.0 m. It is pulled by a 6.0 N force in the negative x direction. (a) What is the angular momentum of the particle about the origin? (Express your answer in vector form.) (b) What torque about the origin acts on the particle? (Express your answer in vector form.)...
At the instant the displacement of a 2.00 kg object relative to the origin is ?...
At the instant the displacement of a 2.00 kg object relative to the origin is ? ⃗ = (2.00 ?)?̂ + (4.00 ?)?̂ − (3.00 ?)? ̂ its velocity is ? ⃗ = −(6.00 ? ? )?̂ + (3.00 ? ? )?̂ − (3.00 ? ? )? ̂ and it is subject to a force ? ⃗ = (6.00 ?)?̂ − (8.00 ?)?̂ + (4.00 ?)? ̂. Find (a) the acceleration of the object, (b) the angular momentum of the...
Consider a particle moving through space with velocity v(t) = cos(t)i−sin(t)j + tk. (i) (3 marks)...
Consider a particle moving through space with velocity v(t) = cos(t)i−sin(t)j + tk. (i) Determine its acceleration vector. (ii) Determine the position vector, supposing the particle starts at position (3,−2,3) at time t = 0.
A force F= (3.14t)i+ 6.28j + (1.57t^2)k N acts on a mass of 0.785 kg in...
A force F= (3.14t)i+ 6.28j + (1.57t^2)k N acts on a mass of 0.785 kg in space, with initial velocity v= 7.21i + 9.76j + 3.25k (m/s). At t = 1.71 s, (a) What are the magnitude and direction of the acceleration? (relative to +z axis) (b) What are the magnitude and direction of the velocity? (relative to +y axis) (c) What are the magnitude and direction of the displacement? (relative to +x axis) (d) The angle between the velocity...
At the instant the displacement of a 2.00 kg object relative to the origin is =...
At the instant the displacement of a 2.00 kg object relative to the origin is = (2.00 m) + (4.00 m) - (3.00 m) , its velocity is = - (1.70 m/s) + (9.57 m/s) + (2.99 m/s) and it is subject to a force = (5.04 N) - (9.13 N) + (7.38 N) . Find the acceleration of the object ((a), (b) and (c) for , and components respectively), the angular momentum of the object about the origin ((d),...
A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02...
A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02 m. It is pulled by a 2.09 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j...
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j where x(t) = 10t2 and y(t) = -3t + 2, with x and y in meters and t in seconds. (a) Find the momentum of the particle at time t = 1.00 s. (b) Find the angular momentum about the origin at time t = 3.00 s.
At time t,  r→ = 8.60t2 î - (4.90t + 6.10t2) ĵ gives the position of a...
At time t,  r→ = 8.60t2 î - (4.90t + 6.10t2) ĵ gives the position of a 3.0 kg particle relative to the origin of an xy coordinate system ( r→ is in meters and t is in seconds). (a) Find the torque acting on the particle relative to the origin at the moment 4.50 s (b) Is the magnitude of the particle’s angular momentum relative to the origin increasing, decreasing, or unchanging?
At time t,  r→ = 1.70t2 î - (7.60t + 7.80t2) ĵ gives the position of a...
At time t,  r→ = 1.70t2 î - (7.60t + 7.80t2) ĵ gives the position of a 3.0 kg particle relative to the origin of an xycoordinate system ( r→ is in meters and t is in seconds). (a) Find the torque acting on the particle relative to the origin at the moment 6.50 s (b) Is the magnitude of the particle’s angular momentum relative to the origin increasing, decreasing, or unchanging?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT