Question

Aswer the following question:Be sure to show all your work. Include formulae and units! EVERY TIME! And don

Answer 1

Please refer figure above

We have point A as point of emission of photon (light bulb).
AF = height of bulb = 2 m

Angle DAB = 65^o
BD = 3 metres. D is where photon bends and travels towards second wall.

It strikes at point C.

So, AD = BD/tan65^o
= 3/2.1445
= 1.399 m

DF + AD = 2m
or DF = 2 - 1.399
= 0.601 m

Alos CE = EB*tan20^o
EB = 2m
So, CE = 2*tan20^o
= 0.728 m

EG = DF = 0.601 m
So,

CG = EG + CE
= 0.601+0.728
= 1.329 m

So, photon strikes 1.329 m above floor on second wall.