Question

An industrial laser cutting tool has a peak electric field of 6.0E5 V/m. What is the...

An industrial laser cutting tool has a peak electric field of 6.0E5 V/m. What is the average intensity of the laser?

Homework Answers

Answer #1

The average intensity of an electromagnetic wave is given by

Where, is the speed of light, is the permittivity of free space and is the peak electric field in the wave.

Putting the values in SI units in the equation we get

So, the average intensity of the laser is 4.78E8 W/m^2.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 400-W industrial carbon dioxide cutting laser is capable of cutting 3.0-mm thick steel at a...
A 400-W industrial carbon dioxide cutting laser is capable of cutting 3.0-mm thick steel at a rate of 20 mm/s. Carbon dioxide lasers operate at a wavelength of 10.6 μm. The spot size of the cutting laser is 0.16 mm in diameter and the intensity is uniform in this spot. A.What is the magnitude of the Poynting vector for this laser? Express your answer with the appropriate units. B.What is the magnitude of the rms magnetic field for this laser?...
A laser produces an electromagnetic wave with a maximum electric field strength of 1.00×1011 V /...
A laser produces an electromagnetic wave with a maximum electric field strength of 1.00×1011 V / m for a time of 1.00 ns. (a) What is the maximum magnetic field strength in the wave? (b) What is the intensity of the beam? (c) What energy does it deliver on a 1.00-mm2 area?
An industrial laser is used to burn a hole through a piece of metal. The average...
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is = 2.53 × 109 W/m2. What is the rms value of (a) the electric field and (b) the magnetic field in the electromagnetic wave emitted by the laser?
An industrial laser is used to burn a hole through a piece of metal. The average...
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is = 3.74 × 109 W/m2. What is the rms value of (a) the electric field and (b) the magnetic field in the electromagnetic wave emitted by the laser?
An evil scientist’s laser beam has a power output of 0.250 W. (a) If such a...
An evil scientist’s laser beam has a power output of 0.250 W. (a) If such a laser beam is projected onto a circular spot 3.00 mm in diameter, what is its intensity? (b) Find the peak magnetic field strength. (c) Find the peak electric field strength.
In a plane radio wave the maximum value of the electric field component is 6.22 V/m....
In a plane radio wave the maximum value of the electric field component is 6.22 V/m. Calculate (a) the maximum value of the magnetic field component and (b) the wave intensity.
What is the maximum value of the electric field in an electromagnetic wave whose average intensity...
What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 3.05 W/m2 ? Answer is in V/m
In free space, the electric field intensity ? = 20 cos (ωt-50x) ?̂ V/m. ?̂ is...
In free space, the electric field intensity ? = 20 cos (ωt-50x) ?̂ V/m. ?̂ is the unit vector along y-axis. Calculate (i) Displacement current density (?? ?? ). (ii) Magnetic Field intensity (?) (iii) Angular frequency (ω). Assume ? 0 = 4? × 10( −7) and ? 0 = 8.854 × 10 (−12) ?/?
An electric field has an electric field strength 6000. N/C at a distance of 1.5 m....
An electric field has an electric field strength 6000. N/C at a distance of 1.5 m. What is the strength of the field at a distance of 6.0 m? 24. An alpha (α) particle is positioned in an electric field such that the gravitational force acting on it is equal to the electrostatic force.              (qα = 3.2 x 10–19 C and mα = 6.64 x 10–27 kg) a) What is the direction of the electric field at this point?...
An electromagnetic wave in vacuum has an electric field amplitude of 321 V/m. Calculate the amplitude...
An electromagnetic wave in vacuum has an electric field amplitude of 321 V/m. Calculate the amplitude of the corresponding magnetic field. _________nT