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A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block,...

A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to rest. (a) What is the average force on the bullet after it strikes the block? (b) If this force is constant, how long does it take the bullet to come to rest?

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Answer #1

Total energy of bullet before hitting the block=kinetic energy of bullet=KE

KE =

m=mass of bullet=4.2g=0.0042kg

v=velocity of bullet=370m/s

Work done after hitting the block=

F=force applied by the bullet

s=distance moved by the block

since F and s are in same direction so W=Fs

now by conservation of energy

KE of bullet before hitting the block=Workdone by the block after hitting the bullet

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