Question

# Two balls moving with the same speed of v = 0.48 m/s but in opposite directions...

Two balls moving with the same speed of v = 0.48 m/s but in opposite directions undergo a head-on collision. Ball A has mass mA = 2.6 kg and is traveling to the left, while ball B has mass mB = 1.3 kg and is traveling to the right. The balls are shown just before the collision in the figure below.

(a) Which ball has the larger momentum (in magnitude) before the collision?

Ball A

Ball B

Both balls have the same momentum (in magnitude) before the collision

(b) Before the collision, the total momentum vector for the system

points to the right.

points to the left.

is zero.

(c) During the collision,

the force ball A applies to ball B is larger in magnitude than the force ball B applies to ball A.

the force ball A applies to ball B is smaller in magnitude than the force ball B applies to ball A.

the force ball A applies to ball B has the same magnitude as the force ball B applies to ball A

(d) Which ball undergoes the larger change in momentum (in magnitude) during the collision?

Ball A.

Ball B.

Both balls undergo the same change in momentum (in magnitude) during the collision.

(e) After the collision, the total momentum vector for the system

points to the right.

points to the left.

is zero

(f) As a result of the collision, the two balls stick together. The speed of the balls after the collision is

0.48 m/s (same as before the collision)

0.24 m/s (half the speed before the collision).

0.16 m/s (one-third the speed before the collision).  please please please rate my answer.

Thank you very much. Best of luck.

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