In the mercury atom, an electron is in the Ec energy level. Two photons are incident upon the electron. Photon 1 has a frequency of 5.28E14 Hz, and Photon 2 has a frequency of 4.37E14 Hz.
a. Calculate which photon will be absorbed, and calculate the new energy level of the electron.
Photon # (blank) will be absorbed.
The new energy level is (blank).
b. Calculate all the possible photon frequencies that the electron can emit to get back down to the Ec energy level from highest to lowest frequency.
(there should be three frequencies).
a) The photon 1 has energy
The photon 2 has energy
Now note that the energy difference between c level and e level of Mercury is
This matches with the frequency of Photon 2. Hence the mercury absorbs Photon 2 and the jumps from c level to e level.
b)
The electron can jump from level e to c in 3 ways. The corresponding frequencies are listed below:
The frequency emitted when the electron jumps from e to d is
The frequency emitted when the electron jumps from d to c is
The frequency emitted when the electron jumps directly from e to c is
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