Solution :
Given :
Mass of the unknown object : m = 20 kg
Specific heat : C = 5 J kg-1 K-1
*** { I think this given quantity is not complete. If the given value is not correct. Please follow the whole process using the actual value. Remaining values will remain same}
Initial temperature : Ti = 350 K
.
And, Volume of water : V = 50 L
So, Mass of the water : mw = 50 kg
Specific heat of water : Cw = 4186 J kg-1 K-1
Initial temperature of water : Tw = 300 K
.
Let the final temperature be Tf.
Then, According to conservation of energy. When the thermal equilibrium is established :
Heat lost by the unknown object = Heat gained by water
∴ m C (T - Tf) = mw Cw (Tf - Tw)
∴ (20)(5)(350 - Tf) = (50)(4186)(Tf - 300)
∴ 35000 - (100)Tf = (209300)Tf - (62790000)
∴ (209400)Tf = 62825000
∴ Tf = 300.024 K
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