Question

Suppose the Earth contains roughly the same amount of the protons and neutrons. Estimate
(a) the number of protons in Earth
(b) the charge Earth would have if all its electrons were removed

Answer 1

a) the mass of the earth is (6 x 10^24 kg),mass of a proton or neutron (1.67 x 10^-27 kg)

(mass earth)/(mass proton) = 3.6 x 10^51= number of protons + neutrons

number of protons=1.8 x 10^51

b)number of proton=numer of electron,,we know that charges neither be created nor be destroyed,if we remove the electron it will ionise into + charge,no of proton we know number of protons=1.8 x 10^51 ,charge on one proton=(1.602 x 10-19 [C]) hence total charge =(1.602 x 10-19 [C])x 1.8 x 10^51=2.8836x 10^22 c