Question

A 48 kg ice skater is gliding along the ice, heading due north at 5.0 m/s. The ice has a small coefficient of static friction, to prevent the skater from slipping sideways, but

Answer #1

KE = 0.5*m*v^2

Since the wind fails to move the skater any to the east there is no
work done in this direction. All the work is done in the N-S
direction. So find the component of the Force in that
direction.

F = 4 cos 45 = 2.76 N

W = F * d = 2.76 N * 90 m

W = 248 N*m

KE1 = Initial kinetic energy

KE2 = kinetic energy after 90 m

The energy after 90 meter equals the initial kinetic energy minus
the energy lost to the work performed by the wind on the
skater.

KE2 = KE1 - W

0.5 m*v2^2 = 0.5 mv1^2 - W

solve for v2

v2 = sqrt[ v1^2 - 2W/m]

v2 = sqrt [(5 m/s)^2 - (2*248 N*m/48 kg)]

v2 = 3.83 m/s

A 48 kg iceskater is gliding along the ice, heading due north at
5.0 m/s. The ice has a small coefficient of static friction, to
prevent the skater from slipping sideways, but

A 55 kg ice skater is gliding along at 3.5 m/s. 5 seconds
later her speed has dropped to 2.9 m/s.
a) What is the magnitude of the kinetic friction acting on her
skates? Ignore!ofair.
b) What is the coefficient of friction between the metal skate
blade and the ice?

At the center of a 50-m-diameter circular ice rink, a 74 kg
skater traveling north at 2.3 m/s collides with and holds onto a 61
kg skater who had been heading west at 3.1 m/s . How long will it
take them to glide to the edge of the rink? Where will they reach
it? Give your answer as an angle north of west.

A 60.0 kg skater moving initially at 3.15 m/s on rough
horizontal ice comes to rest uniformly in 3.85 s due to friction
from the ice. What force does friction exert on the skater? F=
Value? units?

A car with a mass of 1,400 kg and a speed of 15 m/s heading
north approaches an intersection. At the same time, a minivan with
a mass of 1,800 kg and speed of 22 m/s heading east is also
approaching the intersection. The car and the minivan collide and
stick together. What is the velocity of the wrecked
vehicles just after the collision? Ignore friction between
the tires and the surface of the road. (Enter the magnitude
in m/s...

A 62 kg ice skater moving at 3.2 m/s collides with a second
stationary skater with mass 65 kg. The skaters cling together after
the collision and move without friction. Compute their speed after
the collision.

This 80 kg ice
skater moving at 2.5 m/s throws a 200 g puck in the direction he is
moving at 15 m/s relative to the ice.
a. Find the
velocity of the ice skater after throwing the puck. (Ignore
friction)
b. A second
skater who is 60 kg initially at rest catches the puck. Find the
velocity of the second skater after catching the puck.

A skater of mass 60.0 kg standing on ice throws a stone of mass
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the distance over which the skater will move in the opposite
direction if the coefficient of kinetic friction between the skater
and the ice is 0.03.

A 52.0-kg skater is traveling due east at a speed of 3.30 m/s. A
69.5-kg skater is moving due south at a speed of 7.45 m/s. They
collide and hold on to each other after the collision, managing to
move off at an angle ? south of east, with a speed of vf. Find the
following. (a) the angle ? ° (b) the speed vf, assuming that
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A 52.0-kg skater is traveling due east at a speed of 1.10 m/s. A
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collide and hold on to each other after the collision, managing to
move off at an angle south of east, with a speed of vf. Find (a)
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