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A parallel plate capacitor has plates of area A =0.075 m2 separated by distance d =2.30...

A parallel plate capacitor has plates of area A =0.075 m2 separated by distance d =2.30 ✕ 10−5 m and is attached to a battery with potential difference ΔV = 14 V.(The permittivity of free space is εo= 8.85 ✕ 10−12 C2/N·m2).

(a)Calculate the capacitance (in F) if the space between the plates is filled with air.

(b) What is the electric field between the plates of the capacitor?

Suppose that this capacitor is replaced with another with capacitance C = 1.10 ✕ 10−5 F.

(c) What is the energy stored in the new capacitor?

(d) The charging battery is now disconnected and a ceramic slab with dielectric constant κ = 2.30 is slipped between the plates of the new capacitor. What is the energy stored in the capacitor now?

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