Question

A parallel plate capacitor has plates of area A =0.075
m^{2} separated by distance d =2.30 ✕ 10^{−5} m and
is attached to a battery with potential difference ΔV = 14 V.(The
permittivity of free space is ε_{o}= 8.85 ✕
10^{−12} C^{2}/N·m^{2}).

(a)Calculate the capacitance (in F) if the space between the plates is filled with air.

(b) What is the electric field between the plates of the capacitor?

**Suppose that this capacitor is replaced with another
with capacitance C = 1.10 ✕ 10 ^{−5} F.**

(c) What is the energy stored in the new capacitor?

(d) The charging battery is now disconnected and a ceramic slab with dielectric constant κ = 2.30 is slipped between the plates of the new capacitor. What is the energy stored in the capacitor now?

Answer #1

Dear student,

Find this solution, and RATE IT ,If you find it is helpful .your rating is very important to me.If any incorrectness ,kindly let me know I will rectify them soon.

Thanks for asking ..

A parallel plate capacitor has plates of area A =0.075 m2
separated by distance d =1.00 ✕ 10−5 m and is attached to a battery
with potential difference ΔV = 10 V.(The permittivity of free space
is εo= 8.85 ✕ 10−12 C2/N·m2). (a) Calculate the capacitance (in F)
if the space between the plates is filled with air. F (b) What is
the electric field between the plates of the capacitor? Suppose
that this capacitor is replaced with another with...

A parallel plate capacitor has plates of area A =0.055
m2 separated by distance d =2.20 ✕ 10−5 m and
is attached to a battery with potential difference ΔV = 19 V.(The
permittivity of free space is εo= 8.85 ✕
10−12 C2/N·m2).
(a) Calculate the capacitance (in F) if the space between the
plates is filled with air.
(b) What is the electric field between the plates of the
capacitor? In N/C
Suppose that this capacitor is replaced with another...

A parallel plate capacitor has plates of area A =0.055
m2 separated by distance d =1.60 ✕ 10−5 m and is attached to a
battery with potential difference ΔV = 22 V.(The permittivity of
free space is εo= 8.85 ✕ 10−12 C2/N·m2).
calculate the capacitance in F if the space between the plates
is filled with air
what is the electric field between the plates of the
capacitor
suppose the capacitor is replaced with another capacitance C=
1.90 x10^-5 F,...

A parallel-plate capacitor has plates of area 0.16 m2 and a
separation of 1.20 cm. A
battery charges the plates to a potential difference of 180 V and
is then
disconnected. A dielectric slab of thickness 0.4 cm and dielectric
constant K=3 is
then placed symmetrically between the plates.
a) What is the capacitance before the slab is inserted?
b) What is the capacitance with the slab in place?
c) What is the free charge q before the slab is...

A parallel plate capacitor is made from two plates 7 cm^2 in
area, with a plate separation of 3 mm. The capacitor is fully
charged across a 30 V battery, and then disconnected.
How much charge is on the capacitor?
Now material with a dielectric constant of 30 is inserted to
fill the space between the plates, (with the battery disconnected),
What is the charge on the capacitor?
What is the energy stored in the capacitor?
What the field between...

A parallel plate capacitor, in which the space between the
plates is filled with a dielectric material with dielectric
constant κ = 4.7, has a capacitance of C=1,018 μF and it is
connected to a battery whose voltage is V=10 V and fully charged.
Once it is fully charged, it is disconnected from the battery and
without affecting the charge on the plates, dielectric material is
removed from the capacitor.
How much change occurs in the energy of the capacitor;...

A parallel plate capacitor has plates with equal and opposite
charges ±Q , which are initially separated by a distance d . The
capacitor is not connected to a battery. Then, the plates are moved
farther apart so they are now separated by a distance 2d and also a
dielectric with dielectric constant κ=2 that fills the entire space
in the gap is inserted. What happens to the stored energy U and the
potential difference between the plates ΔV=V+−V− after...

A parallel plate capacitor, in which the space between the
plates is filled with a dielectric material with dielectric
constant κ = 6.2, has a capacitance of C=4,650 μF and it is
connected to a battery whose voltage is V=37 V and fully charged.
Once it is fully charged, it is disconnected from the battery and
without affecting the charge on the plates, dielectric material is
removed from the capacitor.
How much change occurs in the energy of the capacitor;...

A parallel plate capacitor with plate separation d is connected
to a battery. The capacitor is fully charged to Q Coulombs and a
voltage of V. (C is the capacitance and U is the stored energy.)
Answer the following questions regarding the capacitor charged by a
battery. For each statement below, select True or False.
After being disconnected from the battery, inserting a
dielectric with κ will increase U.
After being disconnected from the battery, inserting a
dielectric with κ...

An air-filled parallel-plate capacitor with capacitance
C0 stores charge Q on plates separated by
distance d. The potential difference across the plates is
ΔV0 and the energy stored is PEC,0. If the
capacitor is disconnected from its voltage source and the space
between the plates is then filled with a dielectric of constant k =
2.00, evaluate the ratios
(a) Cnew/C0,
(b) ΔVnew/ ΔV0, and
(c) PEC, new/PEC, 0.

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 5 minutes ago

asked 7 minutes ago

asked 15 minutes ago

asked 16 minutes ago

asked 16 minutes ago

asked 20 minutes ago

asked 20 minutes ago

asked 24 minutes ago

asked 33 minutes ago

asked 42 minutes ago

asked 1 hour ago

asked 1 hour ago