Question

A 48 kg iceskater is gliding along the ice, heading due north at 5.0 m/s. The ice has a small coefficient of static friction, to prevent the skater from slipping sideways, but

Answer 1

a) the wind is blowng at 45 degrees to motion

so the force applied by wind along the direction of motion is Fcos 45

work done by wind =- Fcos 45 x X

change in kinetic energy = work done

Vf = 4.09 m/s

b) force actiing perpendicular to motion = Fsin

to balance it

frictional force = Fsin