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A charge Q is transferred from an initially uncharged plastic ball to an identical ball 14cm...

A charge Q is transferred from an initially uncharged plastic ball to an identical ball 14cm away. The force of attraction is then 19mN . How many electrons were transferred from one ball to the other?

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Answer #1

Given Data

r = 14 cm = 0.1 m
F = 19 mN = 0.019 N
k = 8.99*10^9

F = kQ^2 / r2          ---->> solve for Q2

Fr2 / k = Q&2                   ----->> nowplug in numbers

(0.019)(0.14^2) / 8.99*10^9 = Q^2

4.145 X 10^-14 = Q^2        ----->> now square root of both sides

Q = 2.03*10^-7 C

there are 6.25 X 10^18 electrons in 1 Columb, therefore,

(6.25 X 10^18) * (2.03 X 10^-7) = 1.272 X10^12 electrons         ---->> Answer

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