A monatomic gas is cooled by 50
The main principle in this question is the First law of
Thermodynamics
By 1st Law, dQ=dW+dU (using d for delta,nevertheless)
dW=0 as volume is constant
So, dQ=dU
Now, for monoatomic gases, Molar specific heat at constant volume
is given by 3/2.R,where R=gas const.
as dU=nCdT, the values can be substituted to get the only unknown
n, which is the no.of moles.
(Monoatomic is explicitly mentioned so that the Cv of the gas can
be found out based on equipartition of energy)
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