In the following expression, determine the units of the variable , given the units of the other variables: T in seconds (s), Q in coulombs (C), and I in coulombs per second (C/s).
1) x= πQ/VI2
2) x= I√V/T. (square root of V/T)
1) given x= pi Q / V I^2 pi is a number constant it does not have any units. substituting for others we have .Here V is Voltage so unit is Volt(V) dimension of volt is energy/charge = kg m^2 s^(-2)/ C
x = C/ [kg m^2 s^(-2)/C* (C/s)^2] simplifying we get x = s^4 / kg *m^2 this is the unit of x
2) given x = I* = (C/s) * simplifying we get x =C/s *( kg1/2 m / s C1/2 s1/2 )
x = C1/2 *m*kg1/2 / s 5/2
if we keep volt (V) as a standard unit then 1) x = s^2 / V *C.
2 ) x = C/s * V^(1/2) / s^1/2 = C * V^(1/2) /s^3/2
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