The driver of a 800.0 kg car decides to double the speed from
20.3 m/s to 40.6 m/s. What effect would this have on the amount of
work required to stop the car, that is, on the kinetic energy of
the car? KEi=___________×105 J KEf= __________× 105 J |
Get Answers For Free
Most questions answered within 1 hours.