A step-up transformer has a primary coil with 100 loops and a secondary coil with 800 loops. If the primary coil is supplied with a household current of 120V and 12 A,
(a) what voltage is produced in the secondary circuit?
? V
(b) what current flows in the secondary circuit?
? A
Solution:-
If the voltage in the primary is 120v.then the voltage in the secondary is ‘stepped up’ by a factor of, 800/100 or 8
So secondary voltage is, 120v * 8 = 960 V (volt)
The voltage produced in secondary Circuit is 960 V
Conversely the current in the secondary is steeped down by a factor of 8 this gives a secondary current of
12 A / 8 = 1.5 A (ampere)
The current flows in secondary Circuit is 1.5 A
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