Specific Heat
A weight lifter raises 20kg a height of 0.5m. How many times must he do this to burn the 120 Calories in a sports drink?
1 Calorie = 4184 J
120 Calories = 502080 J
Energy required to lift 20 kg is
E = m g h
= ( 20 kg ) ( 9.8 m/s2 ) ( 0.5 m )
= 98 J
Number time he lifts to burn the drink
N = 502080 J / 98 J
=5123.26
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