Question

For the graph of 'Period vs SQRT(L)' with a pendulum

1)What is the expected value of the intercept? Does the intercept of your graph agree with this expected value?Justify your response.

How do I find the expected value of the intercept??

Answer 1

from the oscillation

time period

so all the term in period is constant except length

so period of oscilation is directly proportional to square root of the length

when

L>0, T>0

so the excepted value of intersects is at centre = 0

Use your data to fit

(period) = sqrt(length)
(length) = (period)^2

to get the best fit quadratic, then find the y-intercept of that quadratic, then compute the percent difference between the intercept of the best fit quadratic and the expected value [taking the expected value as the baseline.]