Question

A SCUBA tank, an air tank used for breathing under water, is
initially filled with gas at a pressure of 2.3x10^{7} Pa
and 25 ^{o}C. The tank has a volume of 16.0 L. If the tank
will continue to provide air until it reaches a pressure of
2.5x10^{6} Pa, how many moles of gas will it provide to a
diver diving in water at 6 ^{o}C? Give your answer in moles
to at least three significant figures. Hint: There will be air left
in the tank when the it reaches the lowest pressure the tank can
deliver. The amount of air left might be useful in solving this
problem.

Answer #1

PV = nRT

Initial mole:-

Pi*V = ni*R*Ti

2.3x10^{7} * 16
*10^{-3} = n_{i} * 8.314 *(273.15 +
25)

n_{i} =
2.3x10^{7} * 16 *10^{-3} / 8.314 * 298.15

= 148.457 mole initially

final mole :-

n_{f} =
P_{f} *V / R*T_{f}

= 2.5x10^{6}
* 16 *10^{-3} / 8.314 * 279.15

= 17.235 mole

mole provided = n_{i} -
n_{f} = 148.457 - 17.235

**= 131.222 mole**

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Please show steps and pictures!

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