What is the frequency of a simple pendulum 2.2 m long (a) in a room, (b) in an elevator accelerating upward at a rate of 1.2 m/s2, and (c) in free fall?
SOLUTION;
L= Length of pendulum =2.2 m
The frequency formula of pendulum is f
a)
f = 0.336 Hz
B)
When acceleration upward then the resultant is=g+a
So, frequency is
C)
When free fall then
T-mg=-mg
T=0
Now, frequency is
f= 0 hz
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