Question

# A uniform magnetic field B = 3.0 x 10-4 T exists in +x direction. A proton...

A uniform magnetic field B = 3.0 x 10-4 T exists in +x direction. A proton (q = +e, and mp = 1.67 x 10-31 kg) shoots through the field in the +y direction with a speed of 5.0 x 106 m/s. Find the magnitude and direction of the force on the proton.

FB = 4.9 x 10-11 N in -x direction

FB = 1.7 x 10-8 N in +y direction

FB = 5.6 x 10-13 N toward us away from the plane of the screen

FB = 2.4 x 10-16 N away from us, towards the plane of the screen

and

What would be the magnitude and direction of force on an electron (q = -e, me = 9.1 x 10-31 kg) had it been in the place of the proton in prob. #1?

FB = 4.9 x 10-11 N away from us, towards the plane of the screen

FB = 5.6 x 10-8 N away from us, towards the plane of the screen

FB = 2.4 x 10-16 N away from us, towards the plane of the screen

FB = 2.4 x 10-16 N toward us, away from the plane of the screen

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