Question

A proton, traveling with a velocity of 3.2 × 10^{6} m/s
due east, experiences a magnetic force that has a maximum magnitude
of 8.2 × 10^{-14} N and direction of due south. What are
the magnitude and direction of the magnetic field causing the
force? If the field is up, then enter a number greater than zero.
If the field is down, then enter a number less than zero.

Answer #1

Thanks you.

A proton, traveling with a velocity of 7.3 × 106 m/s
due east, experiences a magnetic force that has a maximum magnitude
of 8.7 × 10-14 N and direction of due south. What are
the magnitude and direction of the magnetic field causing the
force? If the field is up, then enter a number greater than zero.
If the field is down, then enter a number less than zero.

A proton, traveling with a velocity of 2.7 106 m/s due east,
experiences a maximum magnetic force of 8.0 10-14 N. The direction
of the force is straight down, toward the surface of the earth.
What is the magnitude and direction of the magnetic field B,
assumed perpendicular to the motion?

A proton, traveling with a velocity of 4.9 × 106 m/s
due east, experiences a maximum magnetic force of 8.0 ×
10-14 N. The direction of the force is straight down,
toward the surface of the earth. What is the magnitude and
direction of the magnetic field B, assumed perpendicular
to the motion?
B = Number ___
B) Units ____ ( W,J,No units,V,m,C,T. A, V/m) options
C)____
East, South, West or North
the tolerance is +/-2%

A proton, traveling with a velocity of 6.8 x 106 m/s
due east, experiences a maximum magnetic force of 8.0 x
10-14 N. The direction of the force is straight down,
toward the surface of the earth. What is the magnitude and
direction of the magnetic field B, assumed perpendicular to the
motion?

a proton (positive charge) is traveling due south enters a
region that contains a uniform magnetic field that points due west.
in which direction will the proton be deflected?
a)down
b)up
c)east
d)west
e)north
I know that the answer is down but please explain.

A proton traveling at 4.20 km/s suddenly enters a uniform
magnetic field of 0.770 T , traveling at an angle of 55.0 ∘ with
the field lines
a) Find the magnitude of the force this magnetic field exerts on
the proton.
Express your answer in newtons to three significant figures.
b) If you can vary the direction of the proton's velocity, find
the magnitude of the maximum force you could achieve.
Express your answer in newtons to three significant figures....

An electron in a TV camera tube is moving at 5.80×106 m/s in a
magnetic field of strength 93 mT. Without knowing the direction of
the field, what can you say about the greatest and least magnitude
of the force acting on the electron due to the field?
Maximum force? (in N)
Minimum force? (in N)
At one point the acceleration of the electron is 8.365×1016
m/s2. What is the angle between the electron velocity and the
magnetic field? (deg)...

A group of particles is traveling in a magnetic field of unknown
magnitude and direction. You observe that a proton moving at 1.30
km/s in the +x-direction experiences a force of 2.10×10−16 N in the
+y-direction, and an electron moving at 4.50 km/s in the
−z-direction experiences a force of 8.60×10−16 N in the
+y-direction. What is the magnitude of the magnetic field?
b-What is the direction of the magnetic field? (in the
xz-plane)

A long straight wire carries current to the east in the area
where magnetic field is directed to the south. What is direction of
the force acting on the wire due to magnetic field?
a. North b. South c. Up d. Down e. East f. West g. Zero

A charge of -8.1 µC is traveling at a speed of 8.4
106 m/s in a region of space where there is a magnetic
field. The angle between the velocity of the charge and the field
is 52°. A force of magnitude 4.9 10-3 N acts on the
charge. What is the magnitude of the magnetic field?

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