Question

# A tiempo t = 0, la posición inicial de un objeto es x1 = -9.00 m....

A tiempo t = 0, la posición inicial de un objeto es x1 = -9.00 m. Dos segundos más tarde se encuentra en la posición

x2 = 5.00 m y finalmente se mueve a la posición x3 = -12.0 m para un tiempo total de tres segundos. La velocidad

promedio (en m/s) del objeto en este intervalo de tiempo, es:

```At time t = 0, the initial position of an object is x1 = -9.00 m. Two seconds later he is in position

x2 = 5.00m and finally moves to position x3 = -12.0m for a total time of three seconds. Speed

average (in m / s) of the object in this time interval is:```

average speed = total distance covered/ total time taken

firstly distance travelled from -9 m to +5 = 9+5 = 14 m

next , the distance travelled from +5 m to -12 m = 5+12 = 17 m

therefore, total distance = 14+17 = 31 m ,

which can be also substituted in the above formula as :

= ( 9+5+{5+12})/3

Average speed in 3 seconds of motion = 10.33 m/s

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Thank you.