Applying conservation of momentum, (there is no external force)
Initial momentum = final momentum
initially both bullet(b) and Rifle(r) are in rest before firing the bullet, finally bullet goes too right and rifle will recoil to left
Ub=0 m/s Ur = 0 m/s Vb= 430 m/s Vr = ?
mbUb + mrUr = mbVb - mrVr (negative sign indicates the direction is opposite for recoil)
0 + 0 = (0.0149 * 430) - (4.9*Vr)
(4.9*Vr) = (0.0149 * 430)
Vr= (0.0149 * 430)/4.9
Vr = 1.307 m/s (recoil speed of the rifle)
b) distance of stop, d = 1.38 cm = 0.0138 m
Force exerted on the shoulder, F = mr * a
V2r - U2r =2 * a* d
a = (V2r - 0)/ (2*d) = 1.709/0.0276 = 61.81
F= 4.9 * 61.81 =302.87 N
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