In an L-R-C series circuit, the resistance is 480 ohms, the inductance is 0.360 henrys, and the capacitance is 1.20×10−2 microfarads.
PART A
What is the resonance angular frequency ω0 of the circuit?
Express your answer in radians per second to three significant figures.
PART B
The capacitor can withstand a peak voltage of 570 volts. If the voltage source operates at the resonance frequency, what maximum voltage amplitude Vmax can the source have if the maximum capacitor voltage is not exceeded?
Express your answer in volts to three significant figures.
Given :
R = 480 ohm
L = 0.360 H
C =
A) At resonance angular frequency =
Therefore, putting the values of L and C, we get the value of angular frequency at resonance.
[answer]
B) Maximum voltage the capacitor can withstand is .
Capacitive reactance = .
Current through the capacitor = .
This current through resistor is also same, as they are connected in series.
Therefore, maximum voltage across resistor = .
At resonance, the maximum value of voltage applied = maximum voltage across resistor
= 49.92 V [answer]
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