What is the pressure difference in the tires of a stationary bike versus a bike moving with 30 mph so that the tires temperature are 2.5°C above the ambient temperature of 25°C? Consider that the tires were inflated to 6.5 *105 N/m2 and the ambient pressure is 1.01 * 105 N/m2.
Select one:
a. -0.20 * 105 N/m2
b. -0.06 * 105 N/m2
c. -0.07 * 105 N/m2
d. -0.37 * 105 N/m2
Solution: Given:- Ambient temperature, T1 = ,
Final temperature of tire,
Initial pressure inside tires= 6.5x105 N/m2
Let, P2 be the final pressure inside tire .
Then, using Gay-Lussac's law for ideal gas:
N/m2
The change in pressure = P1-P2
N/m2
N/m2
Therefore, the change in pressure is approx. -0.06 x 105 N/m2. Ans.
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