The input to, and outputs from, three heat engines are listed below. If the temperatures of the hot and cold reservoirs are TH = 600K and TC = 300K in each case, determine for each engine if laws of energy conservation and maximum engine efficiency and are obeyed.
(1) Heat in QH = 50J, Heat out QC = 20J, and Work out Wout = 30J
(2) Heat in QH = 10J, Heat out QC = 7J, and Work out Wout = 4J.
(3) Heat in QH = 30J, Heat out QC = 10J, and Work out Wout = 20J.
efficiency is given as
= 1 - (Tc/Th) = 1 - (300/600) = 0.5
1)
laws of energy conservation is obeyed since
Qh = Qc + Wout : 50 = 20 + 30 = 50
maximum engine efficiency is not obeyed
since = 1 - (Qc/Qh) = 1 - (20/50) = 0.6
2)
laws of energy conservation is not obeyed since
Qh < Qc + Wout : 10 < 7 + 4 = 11
maximum engine efficiency is not obeyed
since = 1 - (Qc/Qh) = 1 - (7/10) = 0.3
c)
laws of energy conservation is obeyed since
Qh = Qc + Wout : 30 = 10 + 20 = 50
maximum engine efficiency is not obeyed
since = 1 - (Qc/Qh) = 1 - (10/30)
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