Question

Calculate the acceleration of a skier heading down a 10.0 slope, assuming the coefficient of friction...

Calculate the acceleration of a skier heading down a 10.0 slope, assuming the coefficient of friction for waxed wood on wet snow (μs = 0.14, μk = 0.10). (b) Find the angle of the slope down which this skier could coast at a constant velocity. You can neglect air resistance.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 79.0-kg skier starts from rest and slides down a 36.0-m frictionless slope that is inclined...
A 79.0-kg skier starts from rest and slides down a 36.0-m frictionless slope that is inclined at an angle of 15.0° with the horizontal. Ignore air resistance. (a) Calculate the work done by gravity on the skier and the work done by the normal force on the skier. Work done by gravity? Work done by normal force? (b) If the slope is not frictionless so that the skier has a final velocity of 4 m/s, calculate the work done by...
Determine the stopping distance for a skier moving down a slope with friction with an initial...
Determine the stopping distance for a skier moving down a slope with friction with an initial speed of 19.0 m/s . Assume that θ = 5.62 deg, g=9.81 m/s2, and that the coefficient of kinetic friction between the skier and the slope is 0.289. Suppose the temperature drops by 2 degrees C and the skier waxes her skis; the coefficient of kinetic friction drops to 0.173. What is now the stopping distance, for the same initial velocity?
A skier of mass 59.0 kg starts from rest at the top of a ski slope...
A skier of mass 59.0 kg starts from rest at the top of a ski slope of height 62.0 m . b)  Now moving horizontally, the skier crosses a patch of soft snow, where the coefficient of friction is μk = 0.250. If the patch is of width 66.0 m and the average force of air resistance on the skier is 180 N , how fast is she going after crossing the patch? c)  After crossing the patch of soft snow, the...
calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope...
calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one ... Question: Calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one that... Calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one that makes an angle of 8.5° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed...
Calculate the maximum deceleration of a car that is heading down a 11.5° slope (one that...
Calculate the maximum deceleration of a car that is heading down a 11.5° slope (one that makes an angle of 11.5° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the static coefficient of friction is involved--that is, the tires are not allowed to slip during the deceleration A) on dry concret B) on wet Concret C) on ice
A skier slides straight down an incline of 25 degrees without using her poles. The slope...
A skier slides straight down an incline of 25 degrees without using her poles. The slope itself is 96 meters long, and the skier starts from rest at the top. a. What would the velocity of the skier be at the bottom of the incline if friction can be neglected? b. What would your answer be to the previous question if the coefficient of kinetic friction between the skis and the snow is 0.13 on the incline? c. Upon reaching...
1.Calculate the magnitude of acceleration of a 74.2 kg snow boarder going up a 7.52^\circ​∘​​ ​​,...
1.Calculate the magnitude of acceleration of a 74.2 kg snow boarder going up a 7.52^\circ​∘​​ ​​, slope assuming the coefficient of friction for waxed wood on wet snow (\mu _s = 0.14,~\mu_k = 0.1μ​s​​=0.14, μ​k​​=0.1). Note that not all of these quantities may be needed. 2.The only forces action on a 4.87 kg object are \vec{F}_1​F​⃗​​​1​​ = 1.56\hat{x}​x​^​​ - 8.64\hat{y}​y​^​​ N, \vec{F}_2​F​⃗​​​2​​ = -7.10\hat{x}​x​^​​ + 7.82\hat{y}​y​^​​ N, and \vec{F}_3​F​⃗​​​3​​ = 9.62\hat{x}​x​^​​ + 1.98\hat{y}​y​^​​ N. If the object is initially at...
This freestyle skier has jumped 10 feet into the air from the tip of the ski...
This freestyle skier has jumped 10 feet into the air from the tip of the ski jump. a) Calculate the initial vertical component of the skiers velocity as they left the tip of the ski jump. b) If the ski jump is at an angle of 40o from the vertical; calculate the magnitude of the initial velocity of the skier. c) If the skier travelled 5 m along the 40o slope before the jump, and the coefficient of kinetic friction...
An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of...
An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts down a distance of 12.7 m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point whose vertical distance is 3.30 m below the edge. How fast is she going just before she...
A skier is skiing down a hill on friction-less skies when he realizes there is a...
A skier is skiing down a hill on friction-less skies when he realizes there is a cliff in front of him. He skies right over the edge and lands on the valley floor. His motion has two parts: on the hill he started at rest and accelerated throughout his trip. Once he comes to the cliff edge, he goes over the side and is experiencing projectile motion through the air, until he lands. Assume the hill makes a 45 degree...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT