At a particular instant, a proton moves toward the east in a uniform magnetic field that is directed straight downward. The magnetic force that acts on it is
Solution) Proton has positive charge q
You can assume coordinate system where you can compare positive X axis to east ( + i) vectorially , similarly positive Y axis as North (+ j ) , negative Y or down is South (- j) and negative X is west ( - i ).
It's velocity now moving east so it's direction is along (+ i ) = V(i)
Since magnetic field is directed straight downward so it's direction is ( - j ) = B( - j )
Magnetic force F is given by
F = qV(i) × B(- j )
F = BqV( i × (- j)) = - BqV( i × j )
We have i × j = k in vectors
F = - BqV(k)
F = BqV( - k )
Here ( - k ) indicates direction is inwards or into
So magnetic force is into .
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