Question

The same concave mirror with a radius of curvature of 1.2meters is mounted on a wall. Now the person stands with the face 0.5 meters from the mirror. Describe the image they see in the mirror: (relative size of the image they see, the orientation of the image, distance from the mirror of the image they see, is the image real or virtual)

Answer 1

Solution: Use mirror formula (1/u) + (1/v) = (1/f)

u = -0.5m, f = - (R/2) = - 0.6m

Put all the values in mirror formula then v= +3m.

Magnification = (-v/u) = 6

Conclusions-

• Distance of image from the mirror is 3m.
• Positive sign of 'v' shows that the image formation is taking place behind the mirror i.e. virtual image.
• Positive sign of magnification shows that image is erect.
• The value of magnification is 6 means size of image is 6 times larger than the size of object.

Thankyou.