Question

To determine focal lengths of converging lenses we can focus an image of a distant object...

To determine focal lengths of converging lenses we can focus an image of a distant object (ex: the trees outside) on a white card. Explain how this yields the focal length. Can this method be used for diverging lenses?

Homework Answers

Answer #1

For distance object light comes from infinite to converging lens and focus on the focal point of lens. Now we can determine the distance of this point from lens which is known as focal length of converging lens. This point is in front of converging lens, hence can be observe.

This method is not helpful for diverging lens. Light coming from far object will diverge. It will not converge as in case of converging lens at focal point. But the diverge rays can be considered that they are coming from a point which is focal point. This point is behind the diverging lens, hence difficult to observe.

I will be glad to see your comment if you have any query and thumb up if you are satisfied. Thanks....

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The focal lengths of the converging and diverging lenses are +15 and -20 cm, respectively. The...
The focal lengths of the converging and diverging lenses are +15 and -20 cm, respectively. The distance between them is 50 cm and the object is placed 10 cm to the left of the converging lens. Determine the location of the final image with respect to the diverging lens. Is this image real or virtual? Find the total magnification; is the image inverse or upright?
The focal lengths of the converging and diverging lenses in the diagram are 8 and -11...
The focal lengths of the converging and diverging lenses in the diagram are 8 and -11 cm, respectively. The distance between the lenses is 22 cm and the object is placed 14 cm to the left of the converging lens. Determine the location of the first image with respect to the first lens (including the sign) q1=  cm. Find the magnification of this image M1=  . Determine the second object distance. p2=  cm. Determine the second (final) image distance with respect to the...
Two lenses, one converging with focal length 20.0 cm and one diverging with focal length -11.7...
Two lenses, one converging with focal length 20.0 cm and one diverging with focal length -11.7 cm , are placed 25.0 cm apart. An object is placed 60.0 cm in front of the converging lens. Determine the position of the final image formed. Express your answer with the appropriate units. di =    Determine the magnification of the final image formed. m=   
Two converging lenses with focal lengths of 40 cm and 19 cm are 10 cm apart....
Two converging lenses with focal lengths of 40 cm and 19 cm are 10 cm apart. A 3.2 cm tall object is 15 cm in front of the 40 cm focal-length lens. Calculate the distance between the final image and the 19 cm focal-length lens and the final image height.
Two converging lenses with focal lengths of 40 cmand 20 cm are 16 cm apart. A...
Two converging lenses with focal lengths of 40 cmand 20 cm are 16 cm apart. A 2.0 cm -tall object is 12 cm in front of the 40 cm -focal-length lens. image postion was calculated to be 78 cm Calculate the image height.
Two converging lenses with the focal lengths f 1 = 0.2 m and f2 = 0.4...
Two converging lenses with the focal lengths f 1 = 0.2 m and f2 = 0.4 m are positioned at a distance f1 + f2 to each other. Such arrangements are called "beam expanders" and are often used in laser technology a) What is the expansion ratio W2 / W1? One of the two converging lenses is now to be replaced by a diverging lens, with the same expansion ratio W2 / W1 to be achieved. b) Which of the...
Two lenses, one converging the other diverging, each have a focal length of 16.5 cm. They...
Two lenses, one converging the other diverging, each have a focal length of 16.5 cm. They both produce virtual images 30 cm from the object. Determine the location of the object and image for each lens and the corresponding magnifications.
A telescope works by taking a distant object, creating an image at the focal point with...
A telescope works by taking a distant object, creating an image at the focal point with the objective lens, and then having the eyepiece lens use that image as its object to create a second image at infinity. Why infinity? So that you don’t need to put your eye in any particular place to see it, and it looks like any other distant object. Q0.1. If both lenses are converging, what should the theoretical magnification be, positive or negative? If...
Focal Length a) Is there a trend in image distances vis-a-vis focal lengths as the object...
Focal Length a) Is there a trend in image distances vis-a-vis focal lengths as the object gets larger? b) How do these distances compare with your essential focal lengths from your projections of distant light source images compared to lens abberations? c) What happens to the thin lens formula when object distance is very large? Write out the formula and explain.
An object is placed 4949 cm to the left of a converging lens of focal length...
An object is placed 4949 cm to the left of a converging lens of focal length 1717 cm. A diverging lens of focal length −20−20 cm is located 1717 cm to the right of the first lens. (Consider the lenses as thin lenses). a) Where is the final image with respect to the second lens?