Question

A person with mass m_{1} = 64 kg stands at the left end
of a uniform beam with mass m_{2} = 91 kg and a length L =
2.7 m. Another person with mass m_{3} = 59 kg stands on the
far right end of the beam and holds a medicine ball with mass
m_{4} = 15 kg (assume that the medicine ball is at the far
right end of the beam as well). Let the origin of our coordinate
system be the left end of the original position of the beam. Assume
there is no friction between the beam and floor.

What is the location of the center of mass of the system?

The medicine ball is thrown to the left end of the beam (and caught). What is the location of the center of mass now?

What is the new x-position of the person at the left end of the beam? (How far did the beam move when the ball was throw from person to person?)

To return the medicine ball to the other person, both people walk to the center of the beam. At what x-position do they end up?

Answer #1

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