Question

A.) How much heat is required to convert 15.0 g of ice at -13.0 ∘C to steam at 100.0∘C ? Express your answer using three significant figures. (Joules)

B.)How much heat is required to convert 15.0 g of ice at -13.0 ∘C to steam at 100.0∘C? Express your answer using three significant figures. (kcal)

Answer 1

Specific Heat of Water, Cw = 4.186 J/gm k
Specific Heat of ice, Ci = 2.108 J/gm k
Specific Heat of Steam, Cs = 1.996 J/gm k
Latent Heat of ice, Li = 333.55 J/gm
Latent Heat of Vaporisation, Ls = 2257 J/gm
Mass of ice , mi = 15 gm

Heat required to convert 15.0 g of ice at -13.0 ∘C to steam at 100.0∘C
Q = mi*Ci*13.0 + mi*Li + mi*Cw*100 + mi*Ls
Q = 15*1.996*13.0 + 15*333.55 + 15*4.186*100 + 15*2257 J
Q = 45526.47 J

(B)
we know 1 Kcal = 4184 J
Converting from Joules to Kcal,
Q = 10.88 Kcal