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How is electrical energy distributed and dissipated in an L-R-C circuit? Please explain.

How is electrical energy distributed and dissipated in an L-R-C circuit? Please explain.

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Answer #1

rate at which eenrgy is distributed is Power

Impendece in RLC circuit is given by Z^2 = R^2+(XL-XC)^2

where XL = inductivereactance = WL = 2pifL

Xc = capcacitve reactnace = 1/WC = 1/(2pifC) =

now current I = V/Z

vOlatge across inductor VL = iXL

Voltage across capacitor Vc = iXC

Volatge across resistor VR = iR

phase angle tan theta = (XL-Xc)/R

power factor cos theta = R/Z

Power across Ressitor Pr = I^2 R

Power across Indcutor PL = I^2 XL

Power across Capacitor Pc = I^2 Xc

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