Question

106kg is hung from the bottom of a steel rod which is initially 4.00000m and 2.00...

106kg is hung from the bottom of a steel rod which is initially 4.00000m and 2.00 cm in diameter. What will the length of the steel rod be after the mass has been added? Young's modulus for this steel is 342MPa (megapascals).

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Answer #1

Given variables

M=106kg

L=4m

D=2cm

Y= 342Mpa

l = ?

Formula:

Solution:

Force at the bottom of rod is

F = mg

Area of rod is

r = D/2

increase in length is 0.00967m and length before adding mass is 4.00000m

Final length will be = l +L = 4.0000 + 0.00967 = 4.00967m

Hence length of steel rod is 4.00967m

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