Question

1) The position of a particle moving along x direction is given
by: x=8t-3t^{2}.What is the velocity of the particle at t=2
s and what is the acceleration?

2) A roller coaster car starts from rest and descends
h_{1}= 40 m. The car has a mass of 75 kg. What is the speed
at 20m while going down the hill?

Answer #1

1)

= 8-6t

velocity at time t= 2s

v = 8-6*2 = -4 m/s

aceeleration a=

a = -6 m/s^{2}

2) from the conservation of energy

mgh_{0} = 1/2 mv^{2} + mgh

v =

=

=19.79 m/s

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