Question

Radius of the middle disk of the 3-step pulley     r = _0.0166_ ( m )  You need this value to calculate the torque applied to the combination of the connected disk and the ring using a string with a mass hanging at the other end.  

Angular acceleration data for the Aluminum disk and the black ring combined.  

Mass m of the brass discs and the plastic mass hanger combined ( kg )	m = 0.025 kg	m = 0.045 kg	m = 0.065 kg	m = 0.085 kg
Absolute value of the angular acceleration |a| ( rad/s2 )	5.035	9.054	13.89	17.99

     Complete the table below.  Use the measured values of the angular acceleration |a| for each of the mass values to calculate the linear acceleration (a).  

                                                                                        

	m = 0.025 kg	m = 0.045 kg	m = 0.065 kg	m = 0.085 kg
Linear acceleration   a = |a| r ( m/s2 )
Force  T = m (g-a)             ( N )
Torque  t=m (g-a)r             ( N*m )

Answer 1

The equations are already given, we just need to put the values

	m = 0.025 kg	m = 0.045 kg	m = 0.065 kg	m = 0.085 kg
Linear acceleration   a = |a| r ( m/s2 )	0.08358	0.1503	0.231	0.2986
Force  T = m (g-a)             ( N )	0.243	0.4342	0.622	0.8076
Torque  t=m (g-a)r             ( N*m )	4.033e-3	7.21e-3	0.01032

the value for Torque  t=m (g-a)r last column is 0.0134 N.m