Question

Granite has a density of 2,750kg/m³ and seawater has a density of 1,050 kg/m³. The statue has a volume of 3.5m³. while the statue is completely under water its lifted at a constant velocity, what is the tension in the rope used to lift the statue? The density of air is 1.225kg/m^3. what is the tension of the suddenly dry rope when the statue is entirely out of water?

Answer 1

here,

density of statue , ps = 2750 kg/m^3

volume of statue , V = 3.5 m^3

mass of statue , m = V * ps

m = 3.5 * 2750 kg = 9625 kg

density of sea water , pw = 1050 kg/m^3

the tension in the rope used to lift statue , T1 = weight - buoyant force

T1 = m * g - pw * V * g

T1 = 9625 * 9.81 - 1050 * 3.5 * 9.81 N

T1 = 5.84 * 10^4 N

when the statue is out of water

the tension in the rope used to lift statue , T2 = weight

T2 = m * g

T2 = 9625 * 9.81 N

T2 = 9.44 * 10^4 N

answered by: anonymous