Modern Physics Question --> Topic: Thermal Radiation & Blackbodies
Q: A 2.30 cm diameter tungsten sphere is heated to a temperature of 2000 degree C. At this temperature tungsten radiates only 30% of the energy radiated by a blackbody of the same size and temperature.
(a) Determine the temperature of a perfectly black spherical body of the same size that radiates at the same rate as the tungsten sphere.
(b) calculate the diameter of a perfectly black spherical body at the same temperature as the tungsten that radiates at the same rate.
Here .
as the rate of radiation of power = 0.30 * rate of radiation of blackbody at this temperature
a) for the same size body ,
let the temperature is T
sigma * 0.30 * Area * (2000 + 273)^4 = sigma * Area * T^4
0.30 * 2273^4 = T^4
solving for T
T = 1682 K = 1409 degree C
the temperature of same sized black body is 1409 degree C
b)
for tha body at the same temperatre ,
let the diameter is d
sigma * T^4 * 0.30 * 4pi * 2.3^2 = sigma * T^4 * 4pi * d^2
0.30 * 4pi * 2.3^2 = 4pi * d^2
solving for d
d = 1.26 cm
the diameter of the spherical body will be 1.26 cm
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