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A .350 kg of ice is initially at temperature of -12 C. How much heat is...

A .350 kg of ice is initially at temperature of -12 C. How much heat is required to melt two-third the mass of the ice only?

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Answer #1

Q = mcT

here, meting the ice means we need to first bring the temperature from -12 C to 0 C then change the phase to water.

It is very obvious that the whole mass of ice will go to 0 C but only 2/3 of it will melt.

_______________

so,

Q = mcT + mLf

where, Lf is heat of fusion

c is specific heat of ice = 2090 J / Kg C

so,

Q = 0.350 * 2090 * 12 + 0.350 * 3.33e5 * 2/3

Q = 8778 + 77700

Q = 86478 J

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