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6. A small 20-turn wire loop of area 5 mm2 is placed inside a long solenoid...

6. A small 20-turn wire loop of area 5 mm2 is placed inside a long solenoid that has 12000 turns/m and carries a sinusoidally varying current i of amplitude 3 A and angular frequency 500 rad/s. The central axes of the loop and solenoid coincide. What are the (a) magnetic field inside the loop? (b) magnetic flux trough the loop? (c) amplitude of emf induced in the loop?

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Answer #1

a) Magnetic field through the loop = Magnetic field inside the solenoid = N I = (4 * 10^-7) * 12000 * (3sin500t)

= 0.0452(Sin500t)

b) Magnetic flux == B.A =  0.0452 (sin500t) * * 5/1000000 = 7.106 * Sin500t

c) Emf induced = = (7.106 * Sin500t)

= 7.106*10^-7 Cos500t*500 = 0.00035530575 Cos500t

Amplitude = 0.00035 m

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