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What is the rms speed of nitrogen molecules contained in a 9.4 m3 volume at 3.9...

What is the rms speed of nitrogen molecules contained in a 9.4 m3 volume at 3.9 atm if the total amount of nitrogen is 2300 mol ?

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Answer #1


Given that

   nitrogen molecule volume V = 9.4 m3

       pressure P = 3.9 atm = 3.9*1.03*10^5 Pa

       number of moles n = 2300 mol

from ideal gas equation PV= nRT ==> T= PV/nR


           T = 3.9*1.03*10^5*9.4/(2300*8.314)
           T = 197.46 k

now the root mean square velocity i s

       Vrms = sqrt(3RT/M)
             = SQRT(3*8.314*197.46 /14) M/S
             = 18.7560 m/s
so V rms = 18.7560 m/s

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