Question

Two long, parallel conductors separated by 14.0 cm carry
currents in the same direction. The first wire carries a current
*I*_{1} = 5.50 A, and the second carries
*I*_{2} = 8.00 A. (Assume the conductors lie in the
plane of the page.)

(a) What is the magnitude of the magnetic field created by
*I*_{1} at the location of
*I*_{2}?

T

(b) What is the force per unit length exerted by
*I*_{1} on *I*_{2}?

magnitude | N/m |

direction | ---Select--- towards wire 1 towards wire 2 |

(c) What is the magnitude of the magnetic field created by
*I*_{2} at the location of
*I*_{1}?

T

(d) What is the force per length exerted by *I*_{2}
on *I*_{1}?

magnitude | N/m |

direction | ---Select--- towards wire 1 towards wire 2 |

In the figure below, the current in the long, straight wire is

*I*_{1} = 3.90 A,

and the wire lies in the plane of the rectangular loop, which
carries 13.2 A. The dimensions shown are *c* = 0.100 m,
*a* = 0.150 m, and ℓ = 0.450 m. Find the magnitude and
direction of the net force exerted by the magnetic field due to the
straight wire on the loop.

magnitude | N |

direction | ---Select--- upward downward to the left to the right into the page out of the page |

Two current-carrying wires lie side by side. The wire on the
left is vertical and current *I*_{1} flows upward
through it. The wire on the right is a rectangular loop with length
*a* and height ℓ. Current *I*_{2} runs
clockwise through the loop. The left wire is a distance *c*
from the left side of the rectangular loop.

HELP w/ BOTH PLEAE w/ CLEAR SOLUTIONS!

Answer #1

**given
d = 14 cm = 0.14 m
I1 = 5.50 A
I2 = 8.00 A**

**a) the magnitude of the magnetic field created by I1 at
the location of I2,**

**B1 = mue*I1/(2*pi*d)**

**= 4*pi*10^-7*5.5/(2*pi*0.14)**

**= 7.86*10^-6 T
<<<<<<<------------Answer**

**b) The force per unit length exerted by I1 and
I2,**

**F/L = B1*I2**

**= 7.86*10^-6*8**

**= 6.29*10^-5 N/m
<<<<<<------------Answer**

**direction : towards wire 1**

**c)
the magnitude of the magnetic field created by I2 at the location
of I1,**

**B2 = mue*I2/(2*pi*d)**

**= 4*pi*10^-7*8/(2*pi*0.14)**

**= 1.14*10^-5 T
<<<<<<<------------Answer**

**d) The force per unit length exerted by I2 and
I1,**

**F/L = B2*I1**

**= 1.14*10^-5*5.5**

**= 6.29*10^-5 N/m
<<<<<<------------Answer**

**direction : towards wire 2**

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