Question

Two long, parallel conductors separated by 14.0 cm carry currents in the same direction. The first...

Two long, parallel conductors separated by 14.0 cm carry currents in the same direction. The first wire carries a current I1 = 5.50 A, and the second carries I2 = 8.00 A. (Assume the conductors lie in the plane of the page.)

(a) What is the magnitude of the magnetic field created by I1 at the location of I2?
T

(b) What is the force per unit length exerted by I1 on I2?

magnitude N/m
direction ---Select--- towards wire 1 towards wire 2


(c) What is the magnitude of the magnetic field created by I2 at the location of I1?
T

(d) What is the force per length exerted by I2 on I1?

magnitude N/m
direction ---Select--- towards wire 1 towards wire 2

In the figure below, the current in the long, straight wire is

I1 = 3.90 A,

and the wire lies in the plane of the rectangular loop, which carries 13.2 A. The dimensions shown are c = 0.100 m, a = 0.150 m, and ℓ = 0.450 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.

magnitude     N
direction     ---Select--- upward downward to the left to the right into the page out of the page

Two current-carrying wires lie side by side. The wire on the left is vertical and current I1 flows upward through it. The wire on the right is a rectangular loop with length a and height ℓ. Current I2 runs clockwise through the loop. The left wire is a distance c from the left side of the rectangular loop.

HELP w/ BOTH PLEAE w/ CLEAR SOLUTIONS!

Homework Answers

Answer #1

given
d = 14 cm = 0.14 m
I1 = 5.50 A
I2 = 8.00 A

a) the magnitude of the magnetic field created by I1 at the location of I2,

B1 = mue*I1/(2*pi*d)

= 4*pi*10^-7*5.5/(2*pi*0.14)

= 7.86*10^-6 T <<<<<<<------------Answer

b) The force per unit length exerted by I1 and I2,

F/L = B1*I2

= 7.86*10^-6*8

= 6.29*10^-5 N/m <<<<<<------------Answer

direction : towards wire 1

c)
the magnitude of the magnetic field created by I2 at the location of I1,

B2 = mue*I2/(2*pi*d)

= 4*pi*10^-7*8/(2*pi*0.14)

= 1.14*10^-5 T <<<<<<<------------Answer

d) The force per unit length exerted by I2 and I1,

F/L = B2*I1

= 1.14*10^-5*5.5

= 6.29*10^-5 N/m <<<<<<------------Answer

direction : towards wire 2

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